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Euler Buckling

Load at which a slender column stops being straight

Pcr = π²EI / (KL)²
Four columns under load showing how they buckle: pinned at both ends K = 1, fixed at one end and free at the other K = 2, fixed at both ends K = 0.5, and fixed at one end and pinned at the other K = 0.7.

Enter units, cross section, end conditions, diameter, outside diameter, width, depth, wall thickness, second moment of area, cross-sectional area, length, modulus of elasticity and yield strength to work out the load at which a slender column stops being straight.

About Euler Buckling

A short column crushes. A long one goes sideways well before the material is anywhere near giving up, and that sideways load is what this works out. It turns on stiffness and shape alone: a mild steel strut and a high tensile one of the same size buckle at exactly the same load, because E is much the same for both.

The ends matter more than anything else on the form. Fix both instead of pinning them and the load goes up four times; leave one free instead of pinned and it drops to a quarter. All of that is the K factor, and the effective length KL it produces is the length of a pinned-pinned column that would fail at the same load.

A column turns about whichever axis is easiest, so the smaller second moment of area is the one that counts. That is the figure taken here for a rectangle, and it is why a plank on edge is far weaker as a strut than its depth suggests.

Euler describes a slender column: one long enough to bend away while the material is still elastic, straight to begin with and loaded down its axis. Real ones are neither straight nor loaded that neatly, and carry less. A stocky column reaches yield before it ever buckles, which puts it outside this altogether — put a yield strength in the panel and it will work out where the changeover falls and say which side yours is on. There is no factor of safety here and this follows no design code.